412. Fizz Buzz

Easy

Given an integer n, return a string array answer (1-indexed) where: - answer[i] == "FizzBuzz" if i is divisible by 3 and 5. - answer[i] == "Fizz" if i is divisible by 3. - answer[i] == "Buzz" if i is divisible by 5. - answer[i] == i (as a string) if none of the above conditions are true.

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        return [fb(n) for n in range(1, n + 1)]


def fb(n: int) -> str:
    if n % 3 == 0 and n % 5 == 0:
        return "FizzBuzz"
    elif n % 3 == 0:
        return "Fizz"
    elif n % 5 == 0:
        return "Buzz"
    else:
        return str(n)